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Let mass of haruyuki be Mh, mass of kuroyukihime be Mk.
Let velocity of haruyuki be Vh, velocity of kuroyukihime be Vk.
By conservation of momentum:
MhUh + MkUk = MhVh + MkVk
It is known that Uh=0,
Thus, MkUk = MhVh + MkVk
MkUk - MkVk = MhVh
(Uk - Vk)Mk = MhVh
Mk/Mh = Vh/(Uk - Vk)
It is known that Mh >> Mk,
Thus, Mk/Mh = 0
Thus, Vh/(Uk - Vk) = 0
Vh = 0
Thus, Uk = -Vk
Conclusion:
haruyuki will not be moved.
kuroyukihime will be deflected.
haruyuki is the one being hit by the car.